12

Episode 5
2D & 3D Trigonometry
Episode 5 — 2D & 3D Trigonometry
General Solution Question 1
Learners will be able to:
• Determine the general solution of a quadratic trigonometric function in the form 2 cos squared b minus 3 cos b is equal to 2. • Rewrite a quadratic equation in the form 2k squared minus 3k minus 2 is equal to 0 by substituting cos b with k. • Factorize a trinomial of the form 2k squared minus 3k minus 2 into (2k plus 1)(k minus 2). • Solve equations of the form 2 cos b plus 1 is equal to zero and cos b minus 2 is equal to zero using the zero product property. • Identify the period of a cosine graph and use it to determine the general solution in the correct quadrants.
SKU: 12-TF-M-T1-W10-E05